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0.5x^2=x^2-2
We move all terms to the left:
0.5x^2-(x^2-2)=0
We get rid of parentheses
0.5x^2-x^2+2=0
We add all the numbers together, and all the variables
-0.5x^2+2=0
a = -0.5; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-0.5)·2
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2}{2*-0.5}=\frac{-2}{-1} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2}{2*-0.5}=\frac{2}{-1} =-2 $
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